I was reading Schneier's blog when I posted a link to his contest in wired. So I went to the link about someone trying to solve it:-
http://www.yesbutnobutyes.com/archives/2009/04/lost_wired_puzz.html

This gave me a idea to add a frequency tag in Hackvertor :)

It works like this:-
1. First param splits the letters up "[\s\n]"
2. Second param splits the words up "\n"

It then loops through the letters and counts how many times they occur, if they appear more than once in a word, if the letters repeat and where they appear in the word. The tag then displays all this information and tries to perform a guess of the word based on frequency of the English language.

Anyway it didn't solve the puzzle but it could be useful in future when I improve it, any comments or suggestions would be cool thanks

http://www.businessinfo.co.uk/labs/hackvertor/hackvertor.php#PEBmcmVxdWVuY3lfMCgiW1xzXG5dIiwiXG4iKT4xNyAxIDIyIDE2IDggNgoyMCAxMSAxOCAxOCAxMCAxNAo3IDcgNSAxOCAyMiA3IDUgNgoyNCAxNSAxMiAxMyAxIDgKNCAzNCAxOCA1NSAxNCA5Mwo1NCA1IDYgMTEgMTAgMTMKMzAgMTIgNiAxOSAyIDIyIDUKMiAxIDExNyAyIDE3IDEgMTc8QC9mcmVxdWVuY3lfMD4%3D

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"People who say it cannot be done should not interrupt those who are doing it.";
labs : [www.businessinfo.co.uk]
blog : [www.thespanner.co.uk]
Hackvertor : [hackvertor.co.uk]