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        <title>Letter/Char frequency</title>
        <description>I was reading Schneier's blog when I posted a link to his contest in wired. So I went to the link about someone trying to solve it:-
http://www.yesbutnobutyes.com/archives/2009/04/lost_wired_puzz.html

This gave me a idea to add a frequency tag in Hackvertor :) 

It works like this:-
1. First param splits the letters up &amp;quot;[\s\n]&amp;quot;
2. Second param splits the words up &amp;quot;\n&amp;quot;

It then loops through the letters and counts how many times they occur, if they appear more than once in a word, if the letters repeat and where they appear in the word. The tag then displays all this information and tries to perform a guess of the word based on frequency of the English language. 

Anyway it didn't solve the puzzle but it could be useful in future when I improve it, any comments or suggestions would be cool thanks

http://www.businessinfo.co.uk/labs/hackvertor/hackvertor.php#PEBmcmVxdWVuY3lfMCgiW1xzXG5dIiwiXG4iKT4xNyAxIDIyIDE2IDggNgoyMCAxMSAxOCAxOCAxMCAxNAo3IDcgNSAxOCAyMiA3IDUgNgoyNCAxNSAxMiAxMyAxIDgKNCAzNCAxOCA1NSAxNCA5Mwo1NCA1IDYgMTEgMTAgMTMKMzAgMTIgNiAxOSAyIDIyIDUKMiAxIDExNyAyIDE3IDEgMTc8QC9mcmVxdWVuY3lfMD4%3D</description>
        <link>http://sla.ckers.org/forum/read.php?13,28281,28281#msg-28281</link>
        <lastBuildDate>Wed, 22 May 2013 18:21:43 -0500</lastBuildDate>
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            <guid>http://sla.ckers.org/forum/read.php?13,28281,28281#msg-28281</guid>
            <title>Letter/Char frequency</title>
            <link>http://sla.ckers.org/forum/read.php?13,28281,28281#msg-28281</link>
            <description><![CDATA[I was reading Schneier's blog when I posted a link to his contest in wired. So I went to the link about someone trying to solve it:-<br />
http://www.yesbutnobutyes.com/archives/2009/04/lost_wired_puzz.html<br />
<br />
This gave me a idea to add a frequency tag in Hackvertor :) <br />
<br />
It works like this:-<br />
1. First param splits the letters up &quot;[\s\n]&quot;<br />
2. Second param splits the words up &quot;\n&quot;<br />
<br />
It then loops through the letters and counts how many times they occur, if they appear more than once in a word, if the letters repeat and where they appear in the word. The tag then displays all this information and tries to perform a guess of the word based on frequency of the English language. <br />
<br />
Anyway it didn't solve the puzzle but it could be useful in future when I improve it, any comments or suggestions would be cool thanks<br />
<br />
http://www.businessinfo.co.uk/labs/hackvertor/hackvertor.php#PEBmcmVxdWVuY3lfMCgiW1xzXG5dIiwiXG4iKT4xNyAxIDIyIDE2IDggNgoyMCAxMSAxOCAxOCAxMCAxNAo3IDcgNSAxOCAyMiA3IDUgNgoyNCAxNSAxMiAxMyAxIDgKNCAzNCAxOCA1NSAxNCA5Mwo1NCA1IDYgMTEgMTAgMTMKMzAgMTIgNiAxOSAyIDIyIDUKMiAxIDExNyAyIDE3IDEgMTc8QC9mcmVxdWVuY3lfMD4%3D]]></description>
            <dc:creator>Gareth Heyes</dc:creator>
            <category>News and Links</category>
            <pubDate>Wed, 20 May 2009 09:19:23 -0500</pubDate>
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